Question

if you save 1 paise totay 2 paise next day and 3 paise the succeeding day and so on what will be your savings in 365 days?

Answer 1

Answer:

Step-by-step explanation:

Savings=1+2+3+....+365=365*(365+1)/2=365*183=66795paise, hope you understood.

Answer 2

Given:

Savings on successive days.

To find:

Savings in 365 days.

Solution:

The savings in 365 days will be 667.95/-.

According to the question, we can write the savings on successive days as:

1, 2, 3 ...

In the above sequence, the common difference = 1; this sequence forms an Arithmetic progression.

Here, the first term = a = 1; Common difference = 1.

We know that, $S_{n}=\frac{n}{2}[2 a+(n-1) d]$.

So total savings in 365 days will be $S_{365}$.

Now,

$\begin{array}{l}=S_{365}=\frac{365}{2}[2 \times 1+(365-1)(1)] \\\\=\frac{365}{2}[2+364] \\\\=\frac{365}{2}[366]=365 \times 183 \\\\=66795 \text { paise } \\\\=\text { Rs. } 667.95\end{array}$

Therefore, the savings in 365 days will be 667.95/-.