Question

If you tell correct answers for the questions 8,9,10.I will make you brainliest.


with process​

Answer 1

Explanation:

8. P.E=1/2.kx^2

where k is spring constant

2Ep=k given x=1cm

now x=2cm

P.E=1/2×2Ep×4(k=2Ep)

p.E=4Ep

9.F=kx

given F=200N

x=1mm=1×10^-3m

200=k(10^-3)

k=2×10^4

energy=1/2kx^2

=1/2×2×10^4×10^-3

energy= 10J

10.p.e=kq1.q2/r

P.E1/P.E2=R2/R1

=4/2

2:1

Answer 2

Q1) d
Q2) d
Q10)b

Hope it will help you