if you were used Mg place of Au in rutherford experiment what is the results
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Answer:
henchmen
Explanation:
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Answer:
As John Nix points out, the key factor is how thin the foil can be made. For a given radioactive source, the alpha particles will have a certain energy associated with them. The thicker the layer is, the more energy is absorbed, and once all the energy is absorbed, the alpha particles will not reach the sensor.
As it happens, I've used an apparatus to conduct a very similar experiment We tried it on a single layer of gold foil and saw a noticeable drop in the energy compared to shooting the alpha particles at the sensor with no foil barrier. Then we added a second layer of gold foil and saw an even greater drop in the energy. After that, we tried other materials such as iron foil, nickel foil and aluminum foil (ultra-thin, not the sort in your kitchen), and since those are by necessity thicker than gold foil, the energy was even lower. For reference, the gold foil sheets we were using were about 1.3 microns thick, while the aluminum sheets were about 12.7 microns thick (1 micron = 1 one-millionth of a meter).
The data for the aluminum was weaker because it was thicker, so we had more error in our data. However, the gold foil had some problems with it as well, since the thinness of the sheet meant that any imperfections in the sheet were much more noticeable (for the aluminum foil, the fact that it was thicker meant that the surface was much more even on average).
So, to get back to the question, in order to make a magnesium foil work, you would need to use ultra-thin magnesium foil (which would probably still be thicker than the aluminum foil). You would also need an alpha particle source that produces alpha particles with the energy to pass through the sheet. If you had that, as well as the right sort of sensor, callibration equipment and vacuum setup to make the apparatus work, then you should be able to produce the same conclusions using a magnesium layer.