Question

someone please help me out with this problem !!​

Answer 1

Step-by-step explanation:

Let the fixed charge be x rupees

And the additional charge be y

Now

27 = 3x+4y .....(eq1)

y = (27-3x) / 4

21 = 3x+2y .....(eq2)

y = (21-3x) /2

Now comparing the values of y

27-3x /4 = 21-3x / 2

(27-3x)2 = (21-3x)4

54 -6x = 84 -12x

6x = 84-54

x = 30/6

x = 5

Now

putting x = 5 in eq1

27 = 3×5 + 4y

27-15 = 4y

y = 12/4

y = 3

So the fixed charge for first three days is 5 rupees

And the additional charge is 3 rupees.

Answer 2

Step-by-step explanation:

$3ruppes \: answer$