Question

if young modulus for steel is 2.0× 10^11 N m^-2 then how much weight be suspended from a steel wire of length 2.0 m and diameter 1.0mm so that the length of the wire be in increased by 1.0mm(g= 9.8ms^-2)

Answer 1

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Answer 2

Dear Student,

◆ Answer -

F = 78.54 N

● Explanation -

# Given -

Y = 2.0× 10^11 Nm^-2

L = 2 m

d = 1 mm = 10^-3 m

l = 1 mm = 10^-3 m

F = ?

# Solution -

Formula for Young's modulus is -

Y = stress / strain

Y = (F/A) / (l/L)

F = Y × πr^2 × l / L

F = 2.0× 10^11 × π×(0.5×10^-3)^2 × 10^-3 / 2

F = 78.54 N

Hence, 78.54 N weight have to be suspended from a steel wire.

Thanks dear. Hope this helps you...