Math, asked by irulebitch, 9 months ago

If yr good at Maths help^.^Pretty plssss

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Answered by tyagibhavishya18
1

Answer:

area of trap = 1/2(5+13)×10

=90mmsq

Answered by MisterIncredible
8

Question :

Find the area of the parallelogram.?

Answer :

1st Method:

To solve this question we have two methods.

What is a Trapezium?

An quadrilateral in which one pair of opposite sides are parallel.

such a quadrilateral is known as a Trapezium .

Formulas related to Trapezium

  1. Perimeter of the Trapezium = sum of all sides.
  2. Area of the Trapezium =

 \frac{1}{2}  \times h(a + b)

Here ,

h represents the distance between the parallel sides.

a and b represents the perpendicular lines

According to the question,

Distance between the parallel sides = 10mm

Perpendicular sides are 5mm & 13mm

However, Substitute their respective values.

That is ,

area =  \frac{1}{2}  \times 10(5 + 13) \\ area =  \frac{1}{2}  \times 10(18) \\ area  = 5(18) \\ area = 90 {mm}^{2}

2nd method :

This method is very simple.

We have to divide the figure into 2 parts.

  1. Rectangle
  2. Triangle

( see the attachment)

Area of the Trapezium = area of the Rectangle + area of the triangle

so,

Area of the rectangle = Length × breadth

= 10mm × 5mm

= 50mm^2

Similarly,

Area of the triangle =

 \frac{1}{2}  \times base \times perpendicular \: height \\ area \:  =  \frac{1}{2}  \times 10 \times 8 \\ area =  \frac{80}{2}  \\ area = 40 {mm}^{2}

Hence,

Area of the Trapezium = area of the rectangle + area of the triangle

[ ar(trap) = area of the Trapezium]

ar(trap) = 50mm^2 + 40mm^2

= 90mm^2

Hence ,

Area of the Trapezium = 90mm^2

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