If z=1+2i and z2=3+i then find z,z2
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Step-by-step explanation:
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i=√-1 complex number
i^2=-1
i^3=-i
i^4=1
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Step-by-step explanation:
z= 1+2i
z-2i=1 ...........(arranging the equation)...(1) and multiplying the whole equation it by 2 we get
2z -4i= 2 ......(1)
z2-i=3
2z-i =3 ........(2)
subtracting of equation (1) by equation (2)
2z-4i=2
2z -i= 3
- + +
--------------
-5i =5
-5i =5
i= -1
put the value of i on equation (1)
z = 1+2i
= 1+ 2(-1)
= -1
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