Math, asked by snehalnandi2018, 21 hours ago

if z=1-i find the imaginary part of z6.

Answers

Answered by abhishekshukla22234
4

Answer:

z=1-i

z^2=(1-i)^2=1+i^2-2i=1-1-2i=-2i

z6=(-2i)^3=-8i^3=-8*-1i=8i

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