If z=1+i,then what is multiplicative inverse of z^2
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Answer:
Multiplicative inverse is -i/2
Explanation:
Given that z=1+i
⇒z²=(1+i)²
=1+i²+2i
=1−1+2i
=2i
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Heya user.......... ❤
Question :If z=1+i,then what is multiplicative inverse of z^2?
Solution :
Given :
z = 1+i
Now,
z^2 = 1+ 2i + i^2 [ Hence, i^2 = -1]
= 2i
So, inverse of z^2 is = 1/2i = -i/ 2
Hope it’s helpful......... ☆(❁‿❁)☆
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