Question

If z=(1+root3+root5) then find 6z²-15Z+24​

Answer 1

Step-by-step explanation:

6(1+√3+√5)^2 -15(1+√3+√5)+24

=6{(1+√3)+√5}^2-15(1+√3+√5)+24

=6{(1+√3)^2+2.(1+√3).√5+(√5)^2}-15(1+√3+√5)+24

=6{1^2+ 2.1.√3+(√3)^2+2√5+2√3.√5+5}-15-15√3-15√5+24

=6 {1+2√3+3+2√5+2√3.√5+5}-15-15√3-15√5+24

=6(9+2√3+2√5+2√3√5)-15-15√3-15√5+24

=54+12√3+12√5+12√3√5-15-15√3-15√5+24

=63-3√3-3√5+12√3√5.

may be right