Question

if |Z| = 1 , then find the value of 1 + z / 1 + z​

Answer 1

Answer:

∣z∣=1

Let z=x+iy

∴

x

2

+y

2

=1

⇒x

2

+y

2

=1

∴

1−z

2

z

=

1−(x

2

−y

2

+2ixy)

x+iy

=

1−x

2

+y

2

−2ixy

x+iy

=

2y

2

−2ixy

x+iy

=

2iy(−iy−x)

x+iy

=

−2iy

1

=

2y

i