If z^2+1/z^2=34 find the value of z^3+1/z^3
Answers
Answered by
27
z² + 1/z² = 34
(z + 1/z)² -2 = 34
(z + 1/z)² = 36
(z + 1/z) = 6
now,
z³ + 1/z³ = (z + 1/z)³ -3(z + 1/z)
= (6)³ - 3(6)
= 216 - 18
= 198
(z + 1/z)² -2 = 34
(z + 1/z)² = 36
(z + 1/z) = 6
now,
z³ + 1/z³ = (z + 1/z)³ -3(z + 1/z)
= (6)³ - 3(6)
= 216 - 18
= 198
Answered by
1
Answer:
Step-by-step explanation:
(z²+1/z²)=18
(z-1/z)²=z²+1/z²-2
(z-1/z)²=18-2
(z-1/z)²=16
z-1/z=√16=4
(z-1/z)³=4³
z³-1/z³-3(z-1/z)=64
z³-1/z³-3×4=64
z³-1/z³=64+12
z³-1/z³=76
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