Question

if z=2-i√7, show that 3z³- 4z²+z+88=0​

Answer 1

Step-by-step explanation:

=> z = 2 – i√7

=> z – 2 = –i√7

=> (z – 2)2 = (–i√7)2

=> z2 – 4z + 4 = –7

=> z2 – 4z + 11 = 0. 3z3 – 4z2 + z + 88 = 3z(z2 – 4z + 11) + 8(z2 – 4z + 11) = 3z(0) + 8(0) =0. please mark me brainlist