if |z| = 2 then find the locus of complex number (a+ bz)
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Answered by
17
|a+bz|=b|ab+z|
if |z|=2
the |ab+z|=2
centre of circle shifted from 0,0 to (-ab,0)
thus
|a+bz|=2b
thus it is a circle
Answered by
25
Step-by-step explanation:
|a+bz|=b|ab+z|
if |z|=2
the |ab+z|=2
centre of circle shifted from 0,0 to (-ab,0)
thus
|a+bz|=2b
thus it is a circle
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