Question

if [z - 3] / 4 - [z + 5] / 8 = [z +2] / 2 then what is the value of z.​

Answer 1

Step-by-step explanation:

$\frac{z - 3}{4} - \frac{z + 5}{8} = \frac{z + 2}{2} \\ \frac{2(z - 3) - (z + 5)}{8} = \frac{z + 2}{2} \\ \frac{2z - 6 - z - 5}{8} = \frac{z + 2}{2} \\ \frac{z - 11}{8} = \frac{z + 2}{2} \\ 2(z - 11) = 8(z + 2) \\ 2z - 22 = 8z + 16 \\ 2z - 8z = 16 - 22 \\ - 6z = - 6 \\ z = \frac{ - 6}{ - 6} = 1$

Answer 2

Step-by-step explanation:

Step-by-step explanation:

\begin{gathered} \frac{z - 3}{4} - \frac{z + 5}{8} = \frac{z + 2}{2} \\ \frac{2(z - 3) - (z + 5)}{8} = \frac{z + 2}{2} \\ \frac{2z - 6 - z - 5}{8} = \frac{z + 2}{2} \\ \frac{z - 11}{8} = \frac{z + 2}{2} \\ 2(z - 11) = 8(z + 2) \\ 2z - 22 = 8z + 16 \\ 2z - 8z = 16 - 22 \\ - 6z = - 6 \\ z = \frac{ - 6}{ - 6} = 1\end{gathered}4z−3−8z+5=2z+282(z−3)−(z+5)=2z+282z−6−z−5=2z+28z−11=2z+22(z−11)=8(z+2)2z−22=8z+162z−8z=16−22−6z=−6z=−6−6=1