Question

if z=3-5i then prove that z3-10z2+58z-136=0​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

z =3-5 i so that z-3 = -5i

Squaring z^2-6z+9 = -25

z^2 - 6Z +34 = O

Now z^3 - 10z^2 +58z -136 can be written as equal to

(z^2 -6Z + 34)(Z-4)

(0)z-4)

0

Hence Z^3-10z^2 +58z-136= 0