Question

if z=-√3+i then its exponential form is​

Answer 1

Answer: (√4) e^(i5π/6)

Step-by-step explanation:Note: A is used as Theta here

wkt z=-√3+i

So, as we know,

tanA=Imaginary(z) /Real(z)

tanA=-1/√3

tanA=-tan30

tanA=tan(180-30)

tanA=tan150 or tan(5π/6)

A=5π/6

We write the exponential form as

z=|z|e^iA

|z|=√((-√3)^2+1^2)

|z|=√4

z=|z|e^(iA)

=(√4) e^(i5π/6)