if z square = 3-4i, then z=......
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0
Answer:
root of 3-4i
......
......
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4
Answer:
Solve: Z2 = 3 - 4i
Let
z= x + yi
Rewrite as
(x + yi)2 = 3 - 4i
Expand
x2 +2xyi + y2i2 = 3 - 4i
Simplify
x2 - y2 + 2xyi = 3 - 4i
real/imag parts
x2 - y2 = 3
and
2xy = -4
xy = -2
Therefore y = -2/x
Substitute
y = -2/x into x2 - y2 = 3
giving
x^2 - 4/x2 = 3
Multiply by x2
x^4 - 4 = 3x^2
Factor
Roots **>
x^4 - 3x^2 - 4 = 0
(x2 + 1) (x2 - 4) = 0
(x2 + 1) (x + 2) (x - 2) = 0
Given xy = -2
for x = 2 then y = -1 therefore z = 2 - i
for x = -2 then y = 1 therefore z = -2 + i
OK... the 2 solutions for z shown are indicated as correct in the text, but these are the onnly solutions given.
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