If 'z' varies directly as 'x' and inversely
as 'y'. Find the percentage increase in
'z' due to an increase of 12% in x and
a decrease of 20% in y.
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let k be a constant
m be a constant
z=kx
z=m(1/y)
if x increases by 12%
z=k(x+12/100x)
z=kx(112/100)
z=z+12/100z
if x increases by 12% then z increases by 12%
if y decreases by20%
z= m(1/(y-20/100y)
z=m(1/(y(80/100)))
z=m(1/y)(5/4)
z=z+25/100z
if y is decreased by 20% then z increases by 25%
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