Question

If 'z' varies directly as 'x' and inversely
as 'y'. Find the percentage increase in
'z' due to an increase of 12% in x and
a decrease of 20% in y.​

Answer 1

let k be a constant

m be a constant

z=kx

z=m(1/y)

if x increases by 12%

z=k(x+12/100x)

z=kx(112/100)

z=z+12/100z

if x increases by 12% then z increases by 12%

if y decreases by20%

z= m(1/(y-20/100y)

z=m(1/(y(80/100)))

z=m(1/y)(5/4)

z=z+25/100z

if y is decreased by 20% then z increases by 25%

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