if z = x+iy then |3z-5| = 3|z+1| . find the value of The locus of z
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2
Answer:
6x=7
Step-by-step explanation:
If z=x+iy,∣3z−1∣=3∣z−2∣ and then locus of z
Given:
z=x+iy
∣3z−1∣=3∣z−2∣ …… (1)
Substitute the value of z in equation (1).
∣3(x+iy)−1∣=3∣(x+iy)−2∣
Simplify the above equation.
∣3x+3iy−1∣=3∣(x+2)+iy∣
∣(3x−1)+3iy∣=3∣(x+2)+iy∣
(3x−1)
2
+(3iy)
2
=3
(x+2)
2
+(iy)
2
6x
2
+1−6x−9y
2
=9(x
2
+4−4x−y
2
)
1−6x=36−36x
6x=7
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