If Z1=1+i,Z2=3-2i,findZ1+Z2, Z1-Z2, Z1.Z2, Z1/Z2
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Answer:
z1+z2
=1+i+3-2i
=4-1i
z1-z2
=1+i-(+3-2i)
=1+i-3+2i
=-2+3i
z1×z2
(1+i)×(3-2i)
=3+(-2i)+3i-2i²
=3-2i+3i-2i²
=-2i²+3i+3
z1/z2
=1+i/3-2i
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