Question

if z1=2+3i, z2=3-2i then z1-z2=?​

Answer 1

Given:

z1=2+3i

z2=3-2i

z1-z2=?

z1-z2=2+3i-(3-2i)

 =2+3i-3+2i

 =5i-1

Hence the answer is z1-z2=5i-1

Answer 2

Given: Given equations are $z_1=2+3i$ and $z_2=3-2i$.

To find: We have to find $z_1-z_2$.

Solution:

Here i is a imaginary number.

Given values of $z_1,z_2$ are $z_1=2+3i$ and $z_2=3-2i$.

To find the substraction result between $z_1$ and $z_2$ we have to substrate $z_1$ and $z_2$.

By substracting we get-

$z_1 - z_2 = 2 + 3i - 3 + 2i \\ = 5i - 1$

So, the value of $z_1-z_2$ is 5i-1.