Question

If z²+z+1=0, then z^6+z^3+1 =
fast please​

Answer 1

Answer:

We know that, a^3+b^3+c^3 = 3abc if a+b+c=0

Similarly here,

z^2+z+1 = 0 is given,

So, considering, a=z^2,b=z and c=1

we get,

z^6+z^3+1 = (z^2)^3+(z)^3 + 1 = 3*z^2*z = 3z^3