Question

If Zeba is younger by 5 years then what she really is , then the square of her age would have been 11 more than five times her actual age..what is her age now? With proper steps please

Answer 1

Let the present age of Zeba be x yrs. ATP (x-5)^2=11+5x x^2+25-10x=11+5x x^2+25-10x-11-5x=0 x^2-15x+14=0 x^2-x-14x+14=0 x(x-1)-14(x-1)=0 (x-1)(x-14)=0 x=1 (rejected),x=14 Therefore, Present age of Zeba=14 yrs PLZZ mark as brainliest...

Answer 2

Two values of x will be coming but her age is 14years because if x=1 then x-5 will not be possible.