Question

If Zeba was younger by 5 year then what she really is then the square of the her age would have been 11 more than five times the actual age to find her present age represent the above situation by quadratic equation​

Answer 1

Step-by-step explanation:

let the age be X

so (x-5)²=11+5x

x²+25-10x = 11+5x

x²-15x+14=0

x²-14x-x+14=0

x(x-14)-1(x-14)=0

(x-14)(x-1)=0

(x-14)=0 , (x-1)=0

x =14 , x= 1

so her age is 14 as 1 cannot be its age