Question

If zeba were younger by 5 then what is she really is then the square of the age would have been 11 more than five times are actually what is a now

Answer 1

Answer:

55 age of five times of 11

Answer 2

Question:-

If zeba were younger by 5 then what is she really is then the square of the age would have been 11 more than five times are actually what is age now?

Solution:-

•Let the actual age of zeba =x years .

•Her age when she was 5 years younger =(x-5) years.

Now, by given condition

•Square of her age =11 more than five times her actual age

➟ (x-5)²=5x+11

➟ x²+25-10x=5x+11

➟ x²-10x-5x+25-11=0

➟ x²-15+14=0

Factorising the above equation by splitting middle term

➟ x²-14x-x+14=0

➟ x(x-14)-1(x-14)=0

➟ (x-1) (x-14) =0

➟ x-1=0 or x-14=0

∴ x=1 or x=14

➾Note:-Here, x will not be equal to 1 because her age is x-5.So,x-5=1=1-5=-4 I.e, age cannot be negative

Hence,required Zeba's age now is 14 yrs