Question

if zeba were younger by 5 years than what she really is then the square of her age would have been 11 more than five times her actually age. What is her age now?

Answer 1

let age of zeba be x years
then 
(x-5)²=11+5x
x²+25-10x=11+5x
x²-15x+14=0
x²-14x-x+14=0
x(x-14)-1(x-14)=0
x=1 or x=14
her age will be 14 yrs because if she was 1 yea rold the 5 years younger cannot happen

Answer 2

Answer:

Zeba’s present age is 14 years.

To find:

The present age of Zeba

Given:

Assume Zeba’s present age be ‘x’

Five years ago, Zeba’s age will be x-5

As per the given question

$\begin{array} { l } { ( x - 5 ) ^ { 2 } = 11 + 5 x } \\\\ { x ^ { 2 } - 10 x + 25 = 11 + 5 x } \\\\ { x ^ { 2 } - 10 x - 5 x + 25 - 11 = 0 } \\\\ { x ^ { 2 } - 15 x + 14 = 0 } \\\\ { x ^ { 2 } - 14 x - x + 14 = 0 } \\\\ { x ( x - 14 ) - 1 ( x - 14 ) = 0 } \\\\ { ( x - 1 ) ( x - 14 ) = 0 } \\\\ { \text { So } x = 14 ( \text { or } ) x = 1 } \end{array}$

We know that her age cannot be one because if it was one, we cannot go beyond 5 years.

So, now her present age is 14 years.