Question

If Zeff of boron is X then Zeff of Oxygen will be :

Answer 1

Atomic number of Boron = 5

Electronic configuration of Boron = 1S2 2S2 2P1

Effective nuclear charge of boron Zeff = 5 – 2 x 0.35 + 2 x 0.85 = 2.6

Atomic number of Oxygen = 8

Electronic configuration of Oxygen = 1S2 2S2 2P4

Effective nuclear charge of oxygen Zeff = 8 – 5 x 0.35 + 2 x 0.85 = 4.55

Effective nuclear charge of oxygen can be rewritten as 2.6 + 1.95 = 4.55

Consider Zeff of boron as ‘X’, then Zeff of Oxygen is ‘X + 1.95’

Answer 2

Answer:

Atomic number of Boron = 5

Electronic configuration of Boron = 1S2 2S2 2P1

Effective nuclear charge of boron Zeff = 5 – 2 x 0.35 + 2 x 0.85 = 2.6

Atomic number of Oxygen = 8

Electronic configuration of Oxygen = 1S2 2S2 2P4

Effective nuclear charge of oxygen Zeff = 8 – 5 x 0.35 + 2 x 0.85 = 4.55

Effective nuclear charge of oxygen can be rewritten as 2.6 + 1.95 = 4.55

Consider Zeff of boron as ‘X’, then Zeff of Oxygen is ‘X + 1.95’