if zeroes of polynomial xcube-3x aware+X+1 are in a.p
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Answered by
11
Answer:
Step-by-step explanation:
X³-3x²+x+1=0
(x-1)(x²-2x-1)=0
So, x=1,1+√2 and 1-√2 are the roots.
1-√2,1,1+√2 are in AP. Common difference is √2!
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Answered by
3
X³-3x²+x+1=0(x-1)(x²-2x-1)=0
So, x=1,1+√2 and 1-√2 are the roots.
1-√2,1,1+√2 are in AP. Common
difference is √2
hope it helps you
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