if zeroes of the polynomial 3x^2-ax+5 are 2 and b,find the value of a and b
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Answer:
X=2
3x²+ax-14
putting value of x that is 2 we get the value of a because being zero it give 0 after solving.
3×(2)²+a×2-14=0
3×4+2a-14=0
12-14=-2a
-2=-2a
1=a
now putting value of x in second equation,
2x³+bx²+x-2=0
2×(2)³+b×(2)²+2-2=0
2×8+4b=0
16+4b=0
4b=-16
b=-4
putting value of a & b in third equation,
2a+3b
=2×1+3×(-4)
=2-12
=-10
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