If zeroes of the polynomial x2+4x+2a are 2 and 5 tgen find the value of a
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Answered by
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Hey Friend ☺
If 2 is zero of the polynomial p ( x ) = x^2 + 4x + 2a
Then p ( 2 ) = 0
So
p ( 2 ) = x^2 + 4x + 2a .
》0 = ( 2 )^2 + 4 ( 2 ) + 2a
》0 = 4 + 8 + 2a
》0 = 12 + 2a .
》2a = - 12
》a = - 6
Hope it helps you ..!!
✌
If 2 is zero of the polynomial p ( x ) = x^2 + 4x + 2a
Then p ( 2 ) = 0
So
p ( 2 ) = x^2 + 4x + 2a .
》0 = ( 2 )^2 + 4 ( 2 ) + 2a
》0 = 4 + 8 + 2a
》0 = 12 + 2a .
》2a = - 12
》a = - 6
Hope it helps you ..!!
✌
Answered by
0
Hii friend,
2 and 5 are the two zeros of the polynomial X²+4X+2a.
2 and 5 are factor of the given polynomial.
Put X = 5 in P(X)
P(X) = X²+4X+2a
P(2) = (2)² + 4 × 2 + 2a
4 + 8 + 2a = 0
12+2a = 0
2a = -12
a = -12/2
a = -6.
HOPE IT WILL HELP YOU..... :-)
2 and 5 are the two zeros of the polynomial X²+4X+2a.
2 and 5 are factor of the given polynomial.
Put X = 5 in P(X)
P(X) = X²+4X+2a
P(2) = (2)² + 4 × 2 + 2a
4 + 8 + 2a = 0
12+2a = 0
2a = -12
a = -12/2
a = -6.
HOPE IT WILL HELP YOU..... :-)
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