Question

if zeroes of x(sqr)+(a+1)x+b are2, -3 find (a+b)​

Answer 1

Answer:

I don't know .........

Answer 2

Answer:

a+b = -6

Step-by-step explanation:

x^2 + (a+1) x + b = 0

Sum of the zeros (-a-1) = 2-3 = -1

Product of the zeros (b) = 2×-3 = -6

From this -a-1 = -1

a = 0

b = -6

Asked , a+ b = -6

HOPE THIS HELPS YOU.......