Question

if zeros of polynomiak x^3-3x^2+x+1 are a-b,a,a+b, find a and b​

Answer 1

Answer:

sum of the zeroes = (a-b) + (a+b) + a = 3a i.e. 3a = - b/a

or 3a=3

or a=1

product of the zeroes = (a-b)*(a+b)*a= a3-ab2 i.e. 1 - b2 = c/a (by putting the value a=1)

or b2 =2

or b = +-root2