Question

if zeros of the polynomial x²- 12 x + 32 are a + b and a - b find the value of a and b​

Answer 1

Answer:

Given: p(x)= x^2-12x+32

Zeroes= a+b, a-b

Step-by-step explanation: we know , Sum of zeroes= -b/a; so, (a+b)+(a-b)=12/1 , 2a= 12, a=6

Product of zeroes= c/a; so, (a+b)(a-b)= 32,   a^2-b^2=32..........(1)

Put value of a=6 in eqn 1

6^2-b^2= 32

36-b^2= 32

-b^2=-4

b^2=4

b=2

Hence the values of a and b are 6 and 2 respectively