Question

if zx = 40 cm, zy= 41 cm, xy= ?​

Answer 1

Answer:

$= L\: xyz = 90°\\ = {xy }^{2} = {xz}^{2} + {yz}^{2} \: \: (using \: pythagoras \: theorem) \\ = {xy}^{2} = ( {40}^{2}) + ( {41}^{2}) \\ = {xy}^{2} = {yz}^{2} - {xz}^{2} \\ {xy}^{2} = 1681 - 1600 \\ = xy = 81$

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