Math, asked by seetu23, 1 year ago

if1^3+2^3+3^3+...+9^3=2025 then the value of (0.11)^3+(0.22)^3+(0.33)^3+...+(0.99)^3 is close to

Answers

Answered by mtg2944sharma
15

Answer:

2.695 is the answer

Step-by-step explanation:

( 0.11 ) 3 + ( 0.22 ) 3 + . . . . . . . . . + ( 0.99 ) 3 = ( 0.11 ) 3 [ 1 3 + 2 3 + 3 3 + . . . . . . + 9 3 ]  = 0.001331 × 2025 = 2.695275 = 2.695  (approx)

Answered by PraneethKumar2006
1

Answer:

(0.11)^3+(0.22)^3+.....+ (0.99)^3 = 0.11^3(1^3 +2^3+.....+9^3)= 0.11^3(2025) = 2.695275

Step-by-step explanation:

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