If2powerx=3powery=6 power-z then 1/x +1/y +1/z is equal
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Hello Mate!
2^x = 3^y = 6^-z = k
2 = k^(1/x)
3 = k^(1/y)
6 = k^(-1/z)
2 × 3 = 6
k^(1/x) × k^(1/y) = k^(-1/z)
Since, base are in multiplication so powers will add up.
1 / x + 1 / y = - 1 / z
1 / x + 1 / y + 1 / z = 0
ʜᴇɴᴄᴇ ᴘʀᴏᴠᴇᴅ.
Have great future ahead!
2^x = 3^y = 6^-z = k
2 = k^(1/x)
3 = k^(1/y)
6 = k^(-1/z)
2 × 3 = 6
k^(1/x) × k^(1/y) = k^(-1/z)
Since, base are in multiplication so powers will add up.
1 / x + 1 / y = - 1 / z
1 / x + 1 / y + 1 / z = 0
ʜᴇɴᴄᴇ ᴘʀᴏᴠᴇᴅ.
Have great future ahead!
Krais:
How did u get 2 = k^(1/x)?
Pls tell me pls
2^x = k
2 = k^1/x
Like, 2² = 4
2 = 4^(1/2)
2 = 2
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