if3by5th of a number exceeds its 2by7th by 44, find the number.
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Answered by
2
Let the number is x.
Then by the given question,
x×3/5=x×2/7+44
or, 3x/5-2x/7=44
or, (21x-10x)/35=44
or, 11x=44×35
or, x=(44×35)/11
or, x=4×35
or, x=140
Answered by
1
(3÷5)x - (2÷7)x = 44
(21x-10x) ÷ 35 = 44
11x = 44×35
x = 4×35
x = 140
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