if6/(3√2-2√3)=(a√2+b√3), find a and b
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by rationalising denominator
6×(3√2+2√3)÷(3√2)^2-(2√3)^2=a√2+b√3
6×(3√2+2√3)÷18-12=a√2+b√3
6×(3√2+2√3)÷6=a√2+b√3
3√2+2√3=a√2+b√3
by comparing the equations we can conclude a=3 and b=2
hope this answers helps you please mark my answer as brainiest. follow me for more help.
6×(3√2+2√3)÷(3√2)^2-(2√3)^2=a√2+b√3
6×(3√2+2√3)÷18-12=a√2+b√3
6×(3√2+2√3)÷6=a√2+b√3
3√2+2√3=a√2+b√3
by comparing the equations we can conclude a=3 and b=2
hope this answers helps you please mark my answer as brainiest. follow me for more help.
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