Question

IfA {1,3, 5) and B = {2, 3) then show that n(AxB) = n(BxA) = n(A)xn(B)​

Answer 1

Step-by-step explanation:

n(A) = 3, n(B) =2, n(A) ×n(B) = 6

Then Find A×B = {(1,2),(1,3),(3,2),(3,3),(5,2),(5,3)}

Therfore n(A×B) = 6

Let is Find B×A = {(2,1),(2,3),(2,5),(3,1),(3,3),(3,5)}

Therefore n(B×A) = 6

n(A)×n(B) = n(A×B) = n(B×A) = 6

Hence Proved