Math, asked by nandlalsss1978, 1 year ago

Ifa^2-b^2=(a+b)(a-b),then find the value of 104×96

Answers

Answered by Anantbhattal
1

Answer:

104=100+4

96=100-4

using the identity mentioned in ques.

(100+4)(100-4)

=(100)^2-(4)^2

=10000-16

=9984

Answered by nitin6071
1

Answer:9984

Step-by-step explanation:

If a^2-b^2=(a+b)(a-b)

Then 104×96 will be

(100+4)(100-4)=(100)^2-(4)^2

=10000-16

=9984

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