Ifa^2-b^2=(a+b)(a-b),then find the value of 104×96
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Answered by
1
Answer:
104=100+4
96=100-4
using the identity mentioned in ques.
(100+4)(100-4)
=(100)^2-(4)^2
=10000-16
=9984
Answered by
1
Answer:9984
Step-by-step explanation:
If a^2-b^2=(a+b)(a-b)
Then 104×96 will be
(100+4)(100-4)=(100)^2-(4)^2
=10000-16
=9984
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