Ifa + b = 8 and ab = 17,then find a^3+b^3
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a+ b=8 ab=17
(a+b)^3= a^3+b^3+3ab(a+b)
substituting ab=17and a+b = 8
(8)^3=a^3+b^3+3*17(8)
64*8=a^3+b^3+51(8)
512=a^3+b^3+408
Transposing 408 to left hand side
512-408= a^3+a^3
104= a^3+b^3
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