if the sum of a number and its reciprocal is 58 upon
21 find the number
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Solution :-
x/y + y/x = 58 / 21
Use this formula
x/y + y/x = (x² + y²)/xy = 58/21
21 has only one way to combine as a product of 2 integers: 3*7
Double-checking:
x² + y² = 3² + 7² = 9 + 49 = 58
xy = 2*7 = 21
3/7 + 7/3 = 58/21
Ans :- The number is 3/7
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x/y + y/x = 58 / 21
Use this formula
x/y + y/x = (x² + y²)/xy = 58/21
21 has only one way to combine as a product of 2 integers: 3*7
Double-checking:
x² + y² = 3² + 7² = 9 + 49 = 58
xy = 2*7 = 21
3/7 + 7/3 = 58/21
Ans :- The number is 3/7
PLEASE MARK ME AS BRAINLIEST...
nehatomar39039:
please mark me as brainliest
Answered by
0
According to me 3/7 is the number.
hope it help you
hope it help you
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