IfA, B and Care interior angles of a triangle ABC, then show that
cosec(B+C)/2=secA/2
Answers
Answered by
1
Answer:
A+B+C=180 (angle sum property)
A+B=180-C
LHS=cosec(A+B)/2
=cosec(180-C)/2
=cosec 90-C/2
=sec C/2
HENCE PROVED
Similar questions