Ifa+b+c=9 and ab+bc+ca=23 then a3+b3+c3-3abc=
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Step-by-step explanation: As we know that a^3+b^3+c^3-3abc= (a+b+c)(a^2+b^+c^2-ab-bc-ca),
Given,a+b+c=9 and ab+bc+ca=23
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By applying this formula
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We get the answer 108.
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