Ifa+b+c=pi then prove that cos square a/2+cos square b/2-cos square c/2=2cos a/2 cos b/2 sinc/2
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Given: A+B+C=π
L.H.S=cos2A+cos2B+cos2C
=[2cos(A+B)cos(A−B)]+(2cos2C−1)........cosC+cosD=2cos2C+Dcos2C−D
=2cos(180−C)cos(A−B)+2cos2C−1
=−2cosC(cos(A−B)−cosC)−1
=−2cosC(cos(A−B)+cos(A+B))−1
=−2cosC(2cosAcosB)−1
=−4cosAcosBcosC−1
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