Question

ifa,b,r are the zeros of the cubic polynomial x³+5x²+4n​

Answer 1

Answer:

- 4

Step-by-step explanation:

Solution

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x²+5x² +4n

The expression is in the form

ax

3 +bx 2 +cx+d

then

a=1,b=5,c=0,d=4

∴α+β+γ= a−b = 1−5 =−5

αβ+βγ+γα= ac = 10 =0

αβγ= a−d = 1−4 =−4

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Answer 2

Step-by-step explanation:

x³ + 5x² + 4n

→ x³ + 5x² + 0x + 4n

a + b + r = -5

ab + br + ar = 0

abr = -4