ifa wire of resistanceis 6 ohm is fulted frommidpoint so thatits lengthbecomes half then what is new resistance
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it would be reduce by 4 times
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Resistance= Resistivity x length/area
When the wire is stretched to double the length , the area of cross section gets reduced to half.
So
New Resistance = Resistivity x 2length/area/2
I.e,
New resistance = (Resistivity x area/length)x4
i.e, New resistance = Resistance x 4
So when the wire is stretched, the resistance multiplies by four times.
since the resistance is 6 ohm new resistance is 6*4=24ohm
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