Math, asked by rollyk222, 11 months ago

ifa8bc is exactly divisible by1287. find the value of a, b, c

Answers

Answered by vinj224

0

Answer:

1287*3=3849

a8bc is 4 digit no.

multiplier of 1287 should be single digit

1200*4=4800

Multiplier will be less than 4

1287*3 =3849

a=3

b=4

c=9

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