ifbsin A=3/5,fins cos a sec a and tan a
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Given-
Sin A=Perpendicular/Hypotenuse=3/5 ,as we know that 3,4,5 are phythagoras triplet ,so base will be 5 .Then cos a =Base/Hypotenuse=4/5 ,sec a=1/cos a=5/4,tan a=perpendicular/base=3/4.
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